What is the difference between simple interest and compound interest?
Simple interest is calculated only on the original principal, so it is the same every year (SI = P x R x T / 100). Compound interest is calculated on the principal plus the interest already earned, so it grows every year (A = P x (1 + R/100)^T). For 2 years, the difference is P x (R/100)^2.
Explain it simply
You lend Rs.10,000 to a friend at 10% a year.
- With simple interest, your friend pays Rs.1,000 interest every year, always worked out on the original Rs.10,000.
- With compound interest, the first year's Rs.1,000 is added to the amount owed. The second year's interest is 10% of Rs.11,000, which is Rs.1,100. Interest earns interest.
This is why a fixed deposit or a SIP grows faster over long periods, and why unpaid credit card dues grow so quickly.
Example
Question: Find the SI and CI on Rs.10,000 at 10% per annum for 2 years, and the difference between them.
Simple interest: SI = 10,000 x 10 x 2 / 100 = Rs.2,000.
Compound interest:
- After year 1: 10,000 x 1.1 = Rs.11,000.
- After year 2: 11,000 x 1.1 = Rs.12,100.
- CI = 12,100 - 10,000 = Rs.2,100.
Difference: 2,100 - 2,000 = Rs.100. Shortcut: P x (R/100)^2 = 10,000 x (10/100)^2 = 10,000 x 0.01 = 100.
const p = 10000;
const si = p * 10 * 2 / 100;
let amount = p;
for (let year = 1; year <= 2; year++) amount = amount * 110 / 100;
console.log(si); // Output: 2000
console.log(amount - p); // Output: 2100How it works
- SI = P x R x T / 100, and amount = P + SI. It grows in a straight line.
- Compound amount A = P x (1 + R/100)^T, and CI = A - P. It grows faster each year.
- Compounded half-yearly: halve the rate and double the time periods. At 10% a year compounded half-yearly for 1 year, use 5% for 2 periods: 10,000 x 1.05 x 1.05 = Rs.11,025, so CI = Rs.1,025.
- Difference for 2 years: CI - SI = P x (R/100)^2.
- Difference for 3 years: CI - SI = P x (R/100)^2 x (3 + R/100).
- Year 1: SI and CI are always equal for the first year when interest is compounded yearly.
Real-world use
Bank fixed deposits, recurring deposits, home loans and education loans all use compound interest, usually compounded quarterly or monthly. Simple interest shows up in short-term loans and some informal lending. Bank PO, SSC and placement tests ask SI and CI almost every time.
Common mistakes
- Using the SI formula for a CI question, or the other way round.
- Forgetting to change the rate and time when interest is compounded half-yearly or quarterly.
- Reporting the amount when the question asks for the interest. Subtract P.
- Writing the rate as 10 instead of 0.10 inside (1 + R/100).
What to say in the interview
"Simple interest is always on the original principal, so it is P times R times T over 100 and it is the same every year. Compound interest is on the principal plus interest already earned, so the amount is P times (1 + R/100) to the power T. For the first year they are equal, and after that compound interest pulls ahead. For two years the gap is P times (R/100) squared, which is a quick shortcut in tests."
Follow-up questions
- A sum doubles in 5 years at simple interest. What is the rate?
- A sum doubles in 4 years at compound interest. In how many years will it become 8 times?
- Find the difference between CI and SI on Rs.5,000 for 2 years at 8% per annum.
- What is the difference between CI and SI on Rs.10,000 at 10% for 3 years?
Go deeper
Read these once the basics above feel easy.
Answers to the follow-ups:
- Interest = P in 5 years, so P = P x R x 5 / 100, giving R = 20%.
- Doubling takes 4 years. 8 times is 2 x 2 x 2, so it doubles three times: 12 years.
- 5,000 x (8/100)^2 = 5,000 x 0.0064 = Rs.32.
- 10,000 x (0.1)^2 x (3 + 0.1) = 100 x 3.1 = Rs.310. Check: CI = 13,310 - 10,000 = 3,310 and SI = 3,000.
The rule of 72 gives a quick estimate of doubling time under compound interest: years to double is about 72 / R. At 8%, money doubles in about 9 years (the exact value is about 9.01). At 12%, about 6 years. It is an approximation, so use it to check options, not as the final answer when exact figures are asked.
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